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x^2+44x-435=0
a = 1; b = 44; c = -435;
Δ = b2-4ac
Δ = 442-4·1·(-435)
Δ = 3676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3676}=\sqrt{4*919}=\sqrt{4}*\sqrt{919}=2\sqrt{919}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-2\sqrt{919}}{2*1}=\frac{-44-2\sqrt{919}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+2\sqrt{919}}{2*1}=\frac{-44+2\sqrt{919}}{2} $
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